12y^2-32y-12=0

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Solution for 12y^2-32y-12=0 equation:


Simplifying
12y2 + -32y + -12 = 0

Reorder the terms:
-12 + -32y + 12y2 = 0

Solving
-12 + -32y + 12y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-3 + -8y + 3y2) = 0

Factor a trinomial.
4((-1 + -3y)(3 + -1y)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-1 + -3y)' equal to zero and attempt to solve: Simplifying -1 + -3y = 0 Solving -1 + -3y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -3y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -3y = 0 + 1 -3y = 0 + 1 Combine like terms: 0 + 1 = 1 -3y = 1 Divide each side by '-3'. y = -0.3333333333 Simplifying y = -0.3333333333

Subproblem 2

Set the factor '(3 + -1y)' equal to zero and attempt to solve: Simplifying 3 + -1y = 0 Solving 3 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1y = 0 + -3 -1y = 0 + -3 Combine like terms: 0 + -3 = -3 -1y = -3 Divide each side by '-1'. y = 3 Simplifying y = 3

Solution

y = {-0.3333333333, 3}

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